56q^2+17qb-3b^2=0

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Solution for 56q^2+17qb-3b^2=0 equation:


Simplifying
56q2 + 17qb + -3b2 = 0

Reorder the terms:
17bq + -3b2 + 56q2 = 0

Solving
17bq + -3b2 + 56q2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-3b + -7q)(b + -8q) = 0

Subproblem 1

Set the factor '(-3b + -7q)' equal to zero and attempt to solve: Simplifying -3b + -7q = 0 Solving -3b + -7q = 0 Move all terms containing b to the left, all other terms to the right. Add '7q' to each side of the equation. -3b + -7q + 7q = 0 + 7q Combine like terms: -7q + 7q = 0 -3b + 0 = 0 + 7q -3b = 0 + 7q Remove the zero: -3b = 7q Divide each side by '-3'. b = -2.333333333q Simplifying b = -2.333333333q

Subproblem 2

Set the factor '(b + -8q)' equal to zero and attempt to solve: Simplifying b + -8q = 0 Solving b + -8q = 0 Move all terms containing b to the left, all other terms to the right. Add '8q' to each side of the equation. b + -8q + 8q = 0 + 8q Combine like terms: -8q + 8q = 0 b + 0 = 0 + 8q b = 0 + 8q Remove the zero: b = 8q Simplifying b = 8q

Solution

b = {-2.333333333q, 8q}

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